Bar Bending Scheduled Of One Way Slab (BBS)

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Bar Bending Scheduled Of One Way Slab

 

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Bar Bending Scheduled Of One Way Slab (BBS):- Today We are going to discuss the Bar Bending Schedule of One way Slab.

 

BBS is an important thing in building construction or civil engineering.

 

Bar Bending Scheduled Of One Way Slab

 

Bar Bending Scheduled Of One Way Slab
Bar Bending Scheduled Of One Way Slab

 

Given,

 

Diameter of Main Bar              = 12 mm.

 

Diameter of distribution Bar  = 10 mm.

 

Spacing                                   = 150 mm.

 

Top and Bottom Clear Cover   = 25 mm.

 

Slab Thickness                       = 150 mm.

 

Development length (Consider) = 40 d

 

first, We will find out the number of the main bars.

 

Calculation 

 

No. Of Main bars formula =  Length Of Slab / Spacing + 1

 

Bar Bending Scheduled Of One Way Slab

 

Step 1

                                    

1).

 

No. Of Main bars  =    L y  / Spacing + 1 

 

No. Of Main bars  =    6000 / 150 + 1 

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                             = 41 Nos.

 

No. Of Crank bars  = 21 Nos.

 

No. Of Straight Bar = 20 Nos.           

 

2).

 

No. Of Distribution bars  =    L x  / Spacing + 1   

 

No. Of Distribution bars  =    2500 / 150 + 1   

                                             

                                        = 17 Nos.

 

Step 2

 

Cutting length 

 

(i). Cutting Length Of Main Bar (Crank) = Clear span of Slab (L x) + (2 x development Length) + ( 2 x inclined Length) – ( 45* Bend x 4 ) – ( 90* Bend x 2)

 

Cutting Length Of Main Bar (Crank) = 2500+(2 x 40 d) + ( 2 x 0.42 d ) – ( 1 d x 4 ) – ( 2 d x 2 ).

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    Inclined Length = 0.42 D

 

        For 45*        = 1 d

 

        For 90*       = 2 d

 

To understand in details watch the video 

 

 

Cutting Length Of Main Bar (Crank) = 2500+(2 x 40 d) + (2 x 0.42 d) – (1 d x 4) – (2 d x 2).

 

= 2500 + (2 x 40 x 12) + (2 x 0.42 d) – (1 x 12 x 4) –  (2 x 12 x 2).

      

= 2500 + 960 + ( 2 x 0.42 d) – 48 – 48

 

What is D,

 

Bar Bending Schedule of one way Slab

 

D = Slab Thickness – 2 Sides Clear Cover – Diameter of Bars.

 

    = 150 – 50 – 12

  

    = 88 mm.

 

D = 88 mm.

 

Cutting Length = 2500 + 960 + ( 2 x 0.42 x 88) – 96

                        

                        =  3460 + 73.92 – 96  

                        

                        – 3437.92 mm.  or

                        

                        = 3.437 meter

 

Cutting Length Of Main ( Crank ) Bar = 3.437 meter

 

For 21 no. of bars = 21 x 3.437 = 72.177 meter

 

Weight of steel     =  D x D/162 x L

                           

                              = 12 x 12 / 162 x (72.177)

                                  

                              –   0.89 x 72.177

 

                              =     64.23 Kg.

 

 

1(ii). Cutting Length Of Main Bar (straight) = Clear span of slab (Lx) + ( 2 x development length )

            

          = 2500 + ( 2 x 40 d )

 

          – 2500 + ( 2 x 40 x 12 )

 

                  = 2500 + 960 

        

          – 3460 mm or 3.46 meter

 

For 20 No. Of Bars = 20 x 3.46    = 69.2 meter

 

Weight of steel      = 0.89 x 69.2 = 61.58 Kg

 

Bar Bending Schedule Basics: Especially for Freshers Civil Engineers


 

1(ii). Cutting Length Of Distribution Bar 

 

    Length of the slab (L y) – ( Cover on both sides )

 

             = 6000 – 50 = 5950 mm or 5.95 meter

 

 For 17 no. of bars    = 17 x 5.95 = 101.15 meter.

 

 Weight of steel        =  10 x 10 /162 x (101.15)

                               

                                    = 61.70 Kg.

 

 

3).  Extra Top Bar 

                             

( L x / 4 ) / Spacing + 1

                           

=      2500 / 4 x 150 +1

                             

 =  5 Nos.

                                 

For two Sides    =      2 x 5    = 10 Nos.

 

Length Of Extra Top Bar = Length of Same As Distribution Bar.

 

                                         =  5.95 meter

 

For 10 No. Of Bars = 10 x 5.95 = 59.5 meter

 

Weight Of Steel      = 0.89 x 59.5 = 52.95 Kg.

 

Total Wt. Of Steel   = 64.23 + 61.58 + 61.70 + 52.95

 

Total Weight Of  Steel    = 240.46 Kg.

 

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Thanks For the Great Attention!

 

Good Bye & Take Care

 

Happy Learning 

 

Best Recommended Book for Fresher

 

 

Related Post:- 

Bar Bending Schedule of Two way Slab – 1 Best Rule to Calculate

( Column BBS )1 Best Way to Calculate Bar Bending Schedule

Footing Bar Bending Schedule

 

          

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