Bar Bending Schedule of Beam ( BBS )

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Bar Bending Schedule of Beam and BBS of Beam

 

Bar Bending Schedule of Beam
Bar Bending Schedule of Beam

 

BBS and Bar Bending Schedule of Beam

 

Calculation,

 

Long (ALTH) bar = Clear span of beam + Development length – bends

 

= 5000 + 2 x (50D) – 2 x ( 2 D )

 

–  5000 + ( 2 x 50 x 16 ) – ( 2 x 2 x 16 )

 

 = 5000 + 1600 – 64

 

 –  6600 – 64 = 6536 mm or 6.536m

 

Total no. of long (ALTH) bar        = 4 Nos.

 

Then, total length of (ALTH) bar = 4 x 6.536

 

= 26.144 m

 

Bar Bending Schedule of Beam

 

Calculation,

 

Extra Top bar = Length + Development length – bends

 

 = 850 +  (50D) –  ( 2 D )

 

 –  850 + ( 50 x 16 ) – ( 2 x 16 )

 

 = 850 + 800 – 32

 

 –  1650 – 32 = 1618 mm or 1.618 m

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Total no. of Extra top bar = 4 Nos.

 

Then, the total length of the Extra top bar = 4 x 1.618

 

= 6.472 m

 

Bar Bending Schedule of Beam

 

Cutting Length of Stirrup

 

Cutting Length of Stirrup
Bar Bending Schedule of Beam

 

Calculation,

 

A = 500 – 25 – 25 – 4 – 4 = 442 mm

 

B = 230 – 25 – 25 – 4 – 4 = 172 mm

 

Total Length = 2 x ( 442 + 172 ) = 1228 mm

 

Calculation,

 

 

 

Cutting Length = Total Length + Hook – Bends

 

 = 1228  + (10d + 10d) – ( 3 x 2d + 2 x 3d )

 

 –  1228  + 20d – 12d

 

 = 1228  + ( 20 x 8 ) – ( 12 x 8 )

 

 –  1228 + 160 – 96

 

 = 1388 – 96 = 1292 mm 0r 1.292 m

 

No. Of Stirrup in Beam

 

Bar Bending Schedule of Beam

 

S1 Length L.H.S side = Length/Spacing + 1

                                          

= 1050 /100 + 1 = 11 nos.

 

S1 Length R.H.S side = Same as S1 Length L.H.S

 

Side = 11 Nos.

 

S2 Length Middle Side = Length/Spacing – 1

                                           

 = 2900/200 -1 = 13 Nos.

 

Total Length Of Stirrup in Beam

 

Total No .Of Stirrups in Beam = 11 + 13 + 11

 

= 35 Nos.

 

Total Length   = 35 x 1.292 = 45.22 m

 

Weight of Steel of Stirrup in Beam

 

D x D / 162 X L = 8 x 8 /162 x 45.22 = 17.86 kg

                                                        

Weight of Steel of 16 mm bar = 16 x 16 /162 x ( 26.144 + 6.472 )

 

= 1.58 x 32.616

 

= 51.53 kg

 

Weight. Of Stirrups + Weight of Steel of 16 mm bar

   

= 17.86 + 51.53

    

= 69.39 kg

 

Bar Bending Schedule Basics: Especially for Freshers Civil Engineers (Bar Bending Schedule Part-1) Kindle Edition

This Ebook is specially designed for Freshers Civil Engineers. Recommended for Quantity Surveyors & Billing Engineers. Here You Can Learn All Basic Concept & Formulas for Bar Bending Schedule (BBS).

 

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Thanks For the Great Attention!

 

Good Bye & Take Care

 

Happy Learning 

 

Also Read:- 

 

Bar Bending Scheduled Of One Way Slab

Bar Bending Schedule of Two way Slab – 1 Best Rule to Calculate

( Column BBS )1 Best Way to Calculate Bar Bending Schedule

Footing Bar Bending Schedule

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